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A database is the collection of information organized in a systematic and logical manner so that it can be easily accessed, keep up-to-date, and managed. There are different frameworks and models that have come into force to put the collected data in a realistic way. Two key examples of databases include - relational and object-oriented databases. Management of data is carried out with the help of computer programs. These programs are called Database Management systems. For instance, if you want to run any test on a massive dataset, then DBMS tools can be used to fulfill this need. Examples of two key DBMS tools include SQL and Oracle. Database management is all about the user interacting with the database to carry out certain operations. There are many companies that are working hard to manage their valuable asset, i.e., data. The best example that explains it well is Google, which has trillions of pages in its database, but you would be able to fetch the required information with just a single query. This is all made possible by using effective database management tools along with data structure.
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A database is similar to a library where books are stored in a logical way. Few of the database models that are used by many companies include:
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UML's full form is Unified Modeling Language. This is used by software engineers to have a clear idea about the system structure and break the application processes. If you need assistance in writing UML assignments related to the database, then our DBMS experts are available for you round the clock. Students who are taking up part-time jobs or missed a few important database classes find it difficult to write UML assignments when the deadline is impending. You can place an order with us and we deliver it swiftly without comprising on the quality.
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A Graph Database is a database management system that uses graph theory to store, manage and query data. Unlike traditional relational databases, graph databases store data in nodes and edges, which are used to represent entities and relationships, respectively. This structure allows graph databases to provide fast and efficient querying of complex relationships, making them ideal for use cases that require the analysis of complex relationships between entities.
A Database Schema Diagram is a graphical representation of a database’s structure. It shows the relationship between tables, columns, and other elements within a database. This diagram is a useful tool for database designers, as it provides a clear visual representation of the database structure, allowing them to identify and resolve any potential problems before they become an issue.
An Entity Relationship Diagram (ERD) is a graphical representation of entities and their relationships to each other. It is used to model the data structure of a database, and it provides a visual representation of the relationships between tables, columns, and other elements within a database. ERDs are an essential tool for database designers, as they help to ensure that the data structure is well-designed, and that it meets the needs of the business.
A Database Query is a request for data from a database. Queries are typically written in a specific language, such as SQL (Structured Query Language), and are used to retrieve data from a database. Queries can be simple, such as retrieving a single record, or complex, such as aggregating data from multiple tables and performing complex calculations.
Database Modelling is the process of creating a data model for a database. This process involves defining the entities, attributes, and relationships between them, and mapping them to a database schema. The purpose of database modelling is to ensure that the data structure is well-designed and that it meets the needs of the business.
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Question: Database for a theme park - You must create a SQL Script
/*
Name: StudentABCD - 10000010
Project 1
PantherID:
Semester:
*/
-- All your project will create the objects under your own personal database that you will create.
-- Your personal database should have the following name format:
-- First Four letters of last name + underscore + First Name Initial + PantherId
Use StudentABCD_10000010 GO
/*
STEP 1: Create the tables
*/
-- The Job table
CREATE TABLE Job(
jobCode char(4) not null,
jobDesc varchar(50) null,
CONSTRAINT PK_JobCode PRIMARY KEY (jobCode),
CONSTRAINT JOB_JOBCODE CHECK (
jobCode = 'CAST'
OR jobCode = 'ENGI'
OR jobCode = 'INSP'
OR jobCode = 'PMGR'
)
);
GO -- The Employee table
CREATE TABLE Employee(
empNumber char(8) not null,
firstName varchar(25) null,
lastName varchar(25) null,
ssn char(9) null,
address varchar(50) null,
state char(2) null,
zip char(5) null,
jobCode char(4) null,
dateOfBirth date null,
certification bit null,
salary money null,
CONSTRAINT PK_EmpNumber PRIMARY KEY (empNumber),
CONSTRAINT FK_JOB FOREIGN KEY (jobCode) REFERENCES Job(jobCode),
CONSTRAINT EMP_STATECHECK CHECK (
state = 'CA'
OR state = 'FL'
)
);
GO
/*
Step 2: Insert the data
*/
-- Insert the Job table first
Insert into Job
values
('CAST', 'Cast Memeber');
Insert into Job
values
('ENGI', 'Engineer');
Insert into Job
values
('INSP', 'Inspector');
Insert into Job
values
('PMGR', 'Project Manager');
-- Insert the employee
Insert into Employee
values
(
'12345678', 'Michal', 'Nguyen', '111111111',
'8956 Campfire Street Norfolk',
'VA', '23503', 'PMGR', '1-30-1990',
'1', '160000.00'
);
Insert into Employee
values
(
'42378423', 'Marry', 'John', '222222222',
'59 Vernon Court
Independence',
'KY', '41051', 'ENGI', '10-25-1990',
'1', '80000.00'
);
Insert into Employee
values
(
'75834658', 'StudentABCD', 'Kyle',
'333333333', '147 Bank Circle
Oxnard',
'CA', '93035', 'CAST', '01-20-1991',
'0', '35000.00'
);
GO
/*
Step 3: Create Views
*/
-- This View will show the empNumber, firstName, lastName and jobDesc of the employees who are engineers and have a certification value of 1.
CREATE VIEW vw_CertifiedEngineers AS
SELECT
empNumber,
firstName,
lastName,
jobDesc
FROM
Employee,
Job
WHERE
Employee.jobCode = 'ENGI'
AND certification = 1;
GO -- This View will show the empNumber, firstName and lastName of those employees who are over 62
CREATE VIEW vw_ReadyToRetire AS
SELECT
empNumber,
firstName,
lastName
FROM
Employee
WHERE
DateDiff(
year,
dateOfBirth,
GETDATE()
) > 62;
GO -- This view will show the average salary and the employee jobcode grouped per the different job codes.
CREATE VIEW vw_EmployeeAvgSalary AS
SELECT
AVG(salary) as AvgSalary,
jobCode
FROM
Employee
group by
jobCode;
GO
/*
Step 4: Add indexes
*/
-- Index LastName
CREATE INDEX IDX_LastName ON Employee (lastName);
GO -- Index SSN
CREATE INDEX IDX_ssn ON Employee (ssn);
GO
/*
Step 5: Verify Objects
*/
-- Run script Project1Verifier
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